Our experts have made the question series to help students. They have collected the questions from textbook exercises, CBSE sample papers, CBSE past years’ question papers, NCERT Exemplars, and important reference books. They have also solved the questions so that students can follow the answers. Experienced professionals have further checked the solutions to ensure the best quality of the content. Thus, the Important Questions Class 6 Maths Chapter 1 will help students score better in exams. The important questions are-
Question 1.
Fill in the blanks:
(i) One lakh = ………….. ten thousand.
(ii) 1 million = ………… hundred thousand.
(iii) 1 crore = ………… ten lakh.
(iv) 1 crore = ………… million.
(v) 1 million = ………… lakh.
(i) 1 lakh = ten ten thousand.
(ii) 1 million = ten hundred thousand.
(iii) 1 crore = ten ten lakh
(iv) 1 crore = ten million
(v) 1 million = ten lakh
Question 2.
(i) 1 metre = ____millimetres.
(ii) 1 centimetre = ____ millimetres.
(iii) 1 kilometre = ____ millimetres.
(iii) 10, 00, 000
Question 3.
(i) 1 gram = ___ milligrams.
(ii) 1 litre = ___ millilitres.
(iii) 1 kilogram = ___ milligrams.
(iii) 10,00,000
Question 4.
Place the commas correctly and write the numerals :
(i) Seventy-three lakh seventy-five thousand three hundred seven.
(ii) Nine crore five lakh forty-one.
(iii) Seven crore fifty-two lakh twenty-one thousand three hundred two.
(iv) Fifty-eight million four hundred twenty- three thousand two hundred two.
(v) Twenty-three lakh thirty thousand ten.
(i) 73,75,307
(ii) 9,05,00,041
(iii) 7,52,21,302
(iv) 5,84,23,202
(v) 23,30,010.
Question 5.
Insert commas in the numbers suitably and write their names according to the Indian System of Numeration:
(i) 87595762
(ii) 8546283
(iii) 99900046
(iv) 98432701
(i) 8,75,95,762 (Eight crore seventy-five lakh ninety-five thousand seven hundred sixty- two)
(ii) 85,46,283 (Eighty-five lakh forty-six thousand two hundred eighty-three)
(iii) 9,99,00,046 (Nine crore ninety-nine lakh forty-six)
(iv) 9,84,32,701 (Nine crores eighty-four lakh thirty-two thousand seven hundred one)
Question 6.
Insert commas in the numbers suitably and write their names according to the International System of Numeration:
(i) 78921092
(ii) 7452283
(iii) 99985102
(iv) 48049831
(i) 78,921,092 (Seventy-eight million nine hundred twenty-one thousand ninety-two)
(ii) 7,452,283 (Seven million four hundred fifty- two thousand two hundred eighty-three)
(iii) 99,985,102 (Ninety-nine million nine hundred eighty-five thousand one hundred two)
(iv) 48,049,831 (Forty-eight million forty-nine thousand eight hundred thirty-one)
Question 7.
A number in which the Sum of all of its factors is equal to twice the number is called a ___ number.
Question 8.
The numbers which have more than just two factors are called ___ numbers.
Question 9.
Two is the only ___ number which is even.
Question 10.
Two numbers having only one as a common factor are called ___ numbers.
Question 11.
The Lowest Common Multiple ( LCM) of two or more given numbers is always the lowest of their common ___.
Question 12.
The Highest Common Factor (HCF) of two or more than two given numbers is also known as the highest of their common ___.
Question 13.
The product of the place values of the two 2’s in 428721 is
(iii) 400000
(iv) 40000000
(iii): Place the values of 2’s in 428721 are 20000 and 20
∴ The required product = 20000 × 2 = 400000
Question 14.
Number 3 × 10000 + 7 × 1000 + 9 × 100 + 0 × 10 + 4 is the same as
(iii) 37904
(iv) 379409
(ii) : 3 × 10000 + 7 × 1000 + 9 × 100 + 0 × 10 + 4
= 30000 + 7000 + 900 + 4 = 37904
Question 15.
If one is added to the greatest 7-digit number, then it will be equal to
(i) 10 thousand
(ii) 1 lakh
(iii) 10 lakh
(iv) One crore
(iv) : The greatest 7-digit number = 99,99,999
Now, 99,99,999 + 1 = 1,00,00,000
Question 16.
The greatest number in which on rounding off to the nearest thousands gives 5000, is
(iv) : (1) Rounding off 5001 to nearest thousands = 5000
(2) Rounding off 5559 to nearest thousands = 6000
(3) Rounding off 5999 to nearest thousands = 6000
(4) Rounding off 5499 to nearest thousands = 5000
And 5499 > 5001
Question 17.
Keeping the place of six in the number 6350947 same, the smallest number which can be obtained by rearranging other digits is
(i) 6975430
(ii) 6043579
(iii) 6034579
(iv) 6034759
(iii) : Tire new number formed = 6034579
Question 18.
The smallest four-digit number having three different digits is
(iv): The smallest 4-digit number with three different digits is 1002.
Question 19.
The number of all the whole numbers between 38 and 68 is
(iii): There are 29 whole numbers between 38 and 68.
Question 20.
The product of the successor and the predecessor of 999 is
(ii) 998000
(iii) 989000
(ii) : Successor of the number 999 = 999 + 1 = 1000
Predecessor of the number 999 = 999 – 1 = 998
Hence, their product = 998 1000 = 998000
Question 21.
Write in expanded form :
(ii) 574021
(iii) 8907010
(i) 74836 is equal to = 7 × 10000 + 4 × 1000 + 8 × 100 + 3 × 10 + 6 × 1
(ii) 574021 is equal to = 5 × 100000 + 7 × 10000 + 4 x 1000 + 0 × 100 + 2 × 10 + 1 × 1
(iii) 8907010 is equal to = 8 × 1000000 + 9 × 100000 + 0 × 10000 + 7 × 1000 + 0 × 100 + 1 × 10 + 0 × 1
Question 22.
A book exhibition was held for 4 days in a school. The number of the tickets sold on the counter on the first, second, third, and the final day was – 1094, 1812, 2050, and 2751. Find the total number of tickets that sold on all four days.
Number of the tickets sold on the first day = 1094
Number of the tickets sold on the second day = 1812
Number of the tickets sold on the third day = 2050
Number of the tickets sold on the final day = 2751
∴Total number of the tickets sold on all of these four days = 1094 + 1812 + 2050 + 2751 = 7,707.
Question 23.
Shekhar is a famous cricket player. He has so far scored a total of 6980 runs in test matches. He wishes to complete 10,000 runs. How many more runs does he need?
Shekhar has so far scored a total of 6980 runs
He wishes to complete a total of 10,000 runs.
Therefore total number of the runs needed by him are = 10,000 – 6980 = 3020 runs
Question 24.
Which of the following given statements is not true?
(i) Both the addition and multiplication are associative for whole numbers.
(ii) Zero is the identity for the multiplication of whole numbers.
(iii) Addition and multiplication are commutative for whole numbers.
(iv) Multiplication is distributive over addition for whole numbers.
(ii): Zero is the identity for the addition of whole numbers.
Question 25.
(i) 0 + 0 = 0
(ii) 0 – 0 = 0
(iii) 0 × 0 = 0
(iv) 0 – 0 = 0
(iv) : 0 + 0 is not defined.
Question 26.
The predecessor of 1 lakh is
(iii) 999999
(iv) 100001
(ii) : 1 lakh = 100000
∴ Predecessor of 100000 = 100000 – 1 = 99999
Question 27.
The successor of 1 million is
(i) Two million
(ii) 1000001
(iii) 100001
(ii) : 1 million = 1000000
∴ Successor of 1000000 = 1000000 + 1 = 1000001
Question 28.
The number of all the even numbers between 58 and 80 is
(i) : Even numbers between the numbers 58 and 80 are 60, 62, 64, 66, 68, 70, 72, 74, 76, 78.
So, these are ten even numbers between 58 and 80.
Question 29.
The Sum of the number of primes numbers between 16 to 80 and between 90 to 100 is
(iii) : Prime numbers between 16 to 80 are – 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73 and 79.
So, there are total 16 prime numbers between 16 to 80.
Also, 97 is the only one prime number between 90 to 100.
So, there is only one prime number between 90 to 100.
∴ Required sum = 16 + 1 = 17
Question 30.
(i) The HCF of the two distinct prime numbers is 1
(ii) The HCF of two coprime numbers is 1
(iii) The HCF of two consecutive even numbers is 2
(iv) The HCF of an even number and an odd number is always even
(iv): The HCF of an even and an odd number is always said to be an odd number.
Question 31.
In an election, the successful candidate was registered 5,77,500 votes, and his nearest rival had secured 3,48,700 votes. By what total margin did the successful candidate win the election?
Number of the votes secured by the successful candidate = 5,77,500
Number of the votes secured by his nearest rival = 3,48,700
Therefore, margin of the votes is necessary to win the election = 5,77,500 – 3,48,700 = 2,28,800
Question 32.
Kirti bookstore sold books worth a total of ₹2,85,891 in the 1st week of June and books worth a total of ₹4,00,768 in the second week of the month. How much was the total sale for the two weeks together? And in which week was the total sale greater and by how much?
Books sold in the first week of the month June are worth ₹2,85,891
Books sold in the second week of the month are worth ₹4,00,768
Therefore, the total sale of the books in the two weeks together is
= ₹2,85,891 + ₹4,00,768 = ₹6,86,659
In the 2nd week of the month, the sale of total books was greater.
Therefore, the difference in the sale of books
= ₹4,00,768 – ₹2,85,891 = ₹1,14,877
So, in the second week of June, the total sale of books was more than ₹1,14,877.
Question 33.
Find the difference below between the highest and the lowest numbers that is written using the digits 6, 2, 7, 4, and 3, each only once.
Given digits = 6, 2, 7, 4, 3
Greatest number is = 76432
Least number is = 23467
Therefore, difference = 76432 – 23467 = 52,965
Question 34.
A machine, on average, manufactures 2,825 screws a day. How many screws did it produce in January 2006?
The number of screws that are manufactured in a day = 2,825.
Number of screws that are manufactured in month of January = 31 x 2825 = 87,575
Question 35.
The total distance between the school and the house of a student is 1 km and 875 m. Every day she walks both the ways. Find the total distance she covered in six days.
Distance between the school and her house = 1 km 875 m = (1000 + 875) m = 1875 metre.
Total Distance travelled by the student from school to home and from home to school is = 2 x 1875 = 3750 m
Distance travelled by the student in six days is = 3750 m x 6 – 22500 m = 22 km 500 m.
Therefore, the total distance covered in 6 days = 22 km 500 m.
Question 36.
A merchant had ₹78,592 with her. She placed an order to purchase 40 radio sets at ₹1200 each. How much total money will remain with her after the purchase?
Amount of money present with the merchant = ₹78,592
Total Number of the radio sets = 40
Price of one of the radio set = ₹1200
Therefore, the cost of 40 radio sets = ₹1200 x 40 = ₹48,000
Remaining money left with the merchant = ₹78,592 – ₹48000 = ₹30,592
Hence, the amount of ₹30,592 will remain with her after purchasing the following radio sets.
Question 37.
A vessel has four litres and 500 ml of curd. How many total glasses, each of 25 mL capacity, can be filled?
Quantity of the curd in a vessel = 4 l 500 mL = (4 x 1000 + 500) mL = 4500 mL.
Capacity of 1 glass = 25 mL
Therefore the number of glasses = 4500/25
Question 38.
A student has multiplied the number 7236 by 65 instead of multiplying by 56. Calculate by how much was his answer greater than the right answer?
The student had multiplied the number 7236 by 65 instead of multiplying by 56.
The difference between the two above multiplications is = (65 – 56) x 7236 = 9 x 7236 = 65124
(We don’t have to do both the multiplication)
Hence, the answer that is greater than the correct answer is 65,124.
Question 39.
Estimate each of the following given numbers using the general rule:
(i) 730 + 998
(ii) 796 – 314
(iii) 12,904 + 2,888
(iv) 28,292 – 21,496
Rounding off 730 nearest to hundreds = 700
Rounding off 998 nearest to hundreds = 1,000
∴ 730 + 998 = 700 + 1000 = 1700
Rounding off 796 nearest to hundreds = 800
Rounding off 314 nearest to hundreds = 300
∴ 796 – 314 = 800 – 300 = 500
Rounding off 12,904 nearest to thousands = 13000
Rounding off 2888 nearest to thousands = 3000
∴ 12,904 + 2,888 = 13000 + 3000 = 16000
Rounding off 28,292 nearest to thousands = 28,000
Rounding off 21,496 nearest to thousands = 21,000
∴ 28,292 – 21,496 = 28,000 – 21,000 = 7,000
Question 40.
Estimate the following given products using the general rule:
(i) 578 x 161
(ii)5281 x 3491
(iii) 1291 x 592
(iv) 9250 x 29
(i) 578 x 161 = 600 x 200 = 1,20,000
(ii) 5281 x 3491 = 5000 x 3000 = 1,50,00,000
(iii) 1291 x 592 = 1300 x 600 = 7,80,000
(iv) 9250 x 29 = 9000 x 30 = 2,70,000
Question 41.
Which of the following is not true?
(i) (7 + 8) + 9 = 7 + (8 + 9)
(ii) (7 × 8) × 9 = 7 × (8 × 9)
(iii) 7 + 8 × 9 = (7 + 8) × (7 + 9)
(iv) 7 × (8 + 9) = (7 × 8) + (7 × 9)
(iii) : 7 + 8 × 9 = 7 + 72 = 79,
(7 + 8) × (7 + 9) = 15 × 16 = 240
and 79 ≠ 240
Question 42.
The length of the river ‘Narmada’ is 1290 km. Its length in metres is – _____.
As, 1290 km = (1290 × 1000) m = 1290000 m
Question 43.
The total distance between Srinagar and Leh is 422 km. The same distance in metres is – _____.
As, 422 km= (422 × 1000) m = 422000 m
Question 44.
Writing numbers from the greatest to the smallest is called an arrangement in ___ order.
Question 45.
By reversing the order of the digits of the greatest number made by the five different non-zero digits, we get the new number which is the number of _____ five digits.
By reversing the order of the digits of the greatest number made by the five different non-zero digits, the new number present is the smallest number of these digits.
Question 46.
By adding 1 to the greatest ___ digit number, we get the number ten lakh.
As, greatest six-digit number = 999999
By adding one to 999999, we get 1000000.
Question 47.
The number five crore twenty-three lakh seventy-eight thousand four hundred one can also be written, using the commas, in the Indian System of Numeration as.
5, 23, 78, 401
Question 48.
In the Roman Numeration, the symbol X can be subtracted from – ___, M and C only.
Question 49.
The number 66 in Roman numerals is.
LXVI : 66 = LXVI
Question 50.
The total population of Pune was 2,538,473 in 2001. Rounded off to the nearest thousands, the population was ___.
Question 51.
The smallest whole number is ___.
0 : 0 is the smallest whole number.
Question 52.
The successor of number 106159 is ___.
As, Successor of 106159 is 106159 + 1, i.e., 106160
Question 53.
400 is the predecessor of the number ___.
As, 400 is the predecessor of 400 + 1, i.e., 401
Question 54.
___ is the successor of the largest three digit number.
As, Largest three digit number = 999
And the successor of 999 is 999 + 1, i.e., 1000
Question 55.
If the number 7254*98 is to be divisible by the number 22, then the digit at * is
(iii) : 7254 * 98 is divisible by the number 22 only if it is divisible by both 2 and 11.
Given that the number is even. Therefore it is divisible by the number 2.
7254 * 98 is divisible by 11, only if
(7 + 5 + * + 8) – (2 + 4 + 9) or (20 + *) – 15 or 5 + * is also divisible by 11.
∴ The digit at * place should be filled by 6.
Question 56.
The largest number which will always divide the Sum of any pair of consecutive odd numbers is
(ii)The Sum of any pair of the consecutive odd numbers results in the form of a multiple of 4.
∴ The required largest number is 4.
Question 57.
A number is divisible by five and six. It may not be divisible by
(iv): The Least Common Multiple also known as LCM of 5 and 6 is 30.
And also 30 is divisible by the numbers 10, 15 and 30 but not by the number 60.
Question 58.
The greatest number which will always divide the product of the predecessor and successor of an odd natural number other than 1, is
(ii): As the odd natural numbers other than 1 are – 3, 5, 7, 9 and so on.
Now, we know that the predecessor and successor of 3 are – 2 and 4 respectively, and their product is two × four = 8
Similarly, we know that the predecessor and the successor of 5 are – 4 and 6, respectively, and their product is four × 6 = 24.
Thus, the above shows that the greatest number which always divides the product of the predecessor and the successor of an odd natural number other than 1 is 4.
Question 59.
A person had only ₹ 1000000 with him. He purchased a coloured-T.V. for ₹ 16580, a motorcycle for ₹ 45890 and a flat for ₹ 870000. How much money was left with him?
The total amount a person had was = ₹ 1000000
The total amount he spent on a colour T.V. was = ₹ 16580
The amount he spent on a motorcycle was = ₹ 45890
The amount he spent on a flat was = ₹ 870000
∴ Total amount he spent is = ₹ (16580 + 45890 + 870000) = ₹ 932470
Thus, the total amount left with him = ₹ 1000000 – ₹ 932470 = ₹ 67530
Question 60.
Out of 180000 tablets of Vitamin A, a total of 18734 are distributed among the students in the district. Find the total number of remaining vitamin tablets.
Total tablets of Vitamin A are = 180000
Total number of tablets distributed among the students in the district = 18734
∴ The number of total remaining vitamin tablets = 180000 – 18734 = 161266
Question 61.
Chinmay only had ₹ 610000. He gave a total of ₹ 87500 to Jyoti, ₹ 126380 to Javed and ₹ 350000 to John. How much money was left with him?
Chinmay had a total amount = of ₹ 610000
The total amount he gave to Jyoti = ₹ 87500
The total amount he gave to Javed = ₹ 126380
The total amount he gave to John = ₹ 350009
Total amount given by Chinmay is = ₹ (87500 + 126380 + 350000) = ₹ 563880
Thus, the amount left with him
= ₹ 610000 – ₹ 563880 = ₹ 46120
Practise is very important, and it helps students in several ways. Our experts have made the question series to help students in practise. Thus, the questions will help students in several ways, and they will be worthy of their time. The benefits of solving the Important Questions Class 6 Maths Chapter 1 are as follows-
Extramarks is a leading company that provides all the important study materials related to CBSE and NCERT. We provide the CBSE syllabus, CBSE sample papers, CBSE past years’ question papers, CBSE revision notes, CBSE extra questions, NCERT books, NCERT Exemplars, NCERT solutions, NCERT important questions, vital formulas, and many more. Like the Important Questions Class 6 Maths Chapter 1, you will also find important questions for other chapters. The links to the study materials are given below.
Q.1 Which of the following is the representation of number 74 according to roman numerals?
(b). XXXXXXXIV
(d). DCCXLV
Ans (a). LXXIV
Q.2 What is the greatest 7 digit number formed by using the digits 4 , 9 , 1 and 6? Note that each digit should be used at least once.
(a). 99,99,641
(c). 99,66,441
(d). 11,11,469
Given digits:
9 > 6 > 4 > 1
The greatest 7 digit number using the digits 4, 9, 1 and 6 is 99,99,641.
Q.3 Which one of the following is the estimated product of 47 and 215?
Rounding off 215 to the nearest hundreds, we get 200.
Rounding off 47 to nearest tens, we get 50.
Estimated product
Thus, 10,000 is the estimated product of 47 and 215.
Q.4 Write 645340001 using comma in International System of Numeration.
645,340,001
Q.5 a) How many thousands make a million? b) How many lakhs make a crore?
a) 1000 thousands make 1 million. (? 1 million = 1,000,000 = 1000 thousands) b) 100 lakhs make a crore. (? 1 crore = 1,00,00,000 = 100 lakhs)
Cbse important questions for class 6 maths, chapter 2 - whole numbers.
Chapter 4 - basic geometrical ideas, chapter 5 - understanding elementary shapes, chapter 6 - integers, chapter 7 - fractions, chapter 8 - decimals, chapter 9 - data handling, chapter 10 - mensuration, chapter 11 - algebra, chapter 12 - ratio and proportion, chapter 13 - symmetry, chapter 14 - practical geometry, faqs (frequently asked questions), 1. is class 6 maths chapter 1 easy.
The first chapter of Class 6 Maths provides a few basic ideas related to numbers. They will learn how to express bigger numbers, such as in thousands, lakhs, crores, etc. They will also learn how to use commas to write larger number, add or subtract large numbers, etc. This is an easy chapter because most students have ideas regarding lakhs, crores, or other units of numbers. Thus, students won’t have problems understanding the subject matter if they follow the textbook closely. Students can take help from the Important Questions Class 6 Maths Chapter 1 prepared by the experts of Extramarks, and they will find a wide variety of questions to solve.
Practice is very important for getting better marks in exams. Sometimes, more than the textbook exercises are needed, and students should get help from other sources. The experts of Extramarks have made the question series with help from different sources. They have collated the questions from the textbook exercise, CBSE sample papers, CBSE past years’ question papers, and important reference books. They have solved the questions, and experienced professionals have further checked the answers to ensure the best quality of the content. Thus, the Important Questions Class 6 Maths Chapter 1 will help students score better in exams. It will also help boost their confidence and incline interest in the subject matter.
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When you enter the class 6th for the first time, you feel like you are no more just a kid and the course books that have been looking pretty colourful have seen some change in the design. In the same way, your maths textbook is now a bit bulkier, and the chapters are a bit more than just addition, subtraction, multiplication and division. In this article, we will be handling the important questions for class 6 maths chapter 1 which introduces students to a comparison game of numbers where one gets to compare numbers and find out which one is bigger than the other one. In addition to this, students will learn about different ways to line up the numbers and arrange them properly, which is ascending and descending.
Moreover, knowing our numbers in class 6 is important. One needs to have a good knowledge of place values, face values, and problems based on the questions like finding the deciding order of which starts from the highest 6 digit number and more. So Vedantu’s students take out your pens and copies cause this will be a fun session where you will be learning more about your numbers and finding out how they are used in real-life scenarios.
Vedantu is a platform that provides free CBSE Solutions (NCERT) and other study materials for students. You can download NCERT Class 6 Science and Class 6 Maths NCERT Solutions to help you to revise complete syllabus and score more marks in your examinations.
Also, check CBSE Class 6 Maths Important Questions for other chapters:
CBSE Class 6 Maths Important Questions | ||
Sl.No | Chapter No | Chapter Name |
1 | Chapter 1 | Knowing Our Numbers |
2 | Chapter 2 |
|
3 | Chapter 3 |
|
4 | Chapter 4 |
|
5 | Chapter 5 |
|
6 | Chapter 6 |
|
7 | Chapter 7 |
|
8 | Chapter 8 |
|
9 | Chapter 9 |
|
10 | Chapter 10 |
|
11 | Chapter 11 |
|
12 | Chapter 12 |
|
13 | Chapter 13 |
|
14 | Chapter 14 |
|
Very Short Answer Questions (1 Mark)
1. Write the numeration for $80956124$ in the Indian system.
Ans: The numeration for $80956124$ in the Indian system is, $8,09,56,124$.
Eight crore nine lakh fifty-six thousand one hundred twenty-four.
2. Write the notation for Seventy-two crore thirty-one lakh eighty-five thousand seventy-nine.
Ans: Notation: Expressing the numbers in figures. The notation for Seventy-two crore thirty-one lakh eighty-five thousand seventy-nine is, $72,31,85,079$
3. Write $348967954$ separating periods in the Indian system.
Ans: This $34,89,67,954$ can be written in separating periods in the Indian system as below.
Crores | Lakhs | Thousands | Hundreds |
34 | 89 | 67 | 954 |
4. Write the place value and face value of the underlined digit: $95\underline{8}465459$
Ans: The place value and face value of the underlined digit: $95\underline{8}465459$ is,
Place value of $8 \Rightarrow 8\times 1000000=8000000$Face value of $8$ $=8$
5. Write $459769843$ separating periods in the international system.
Ans: Separating periods in international system of $459,769,843$ is,
Millions | Thousands | Hundreds |
$459$ | $769$ | $843$ |
6. Write numerals for eight million, sixty-nine thousand, three hundred ninety-nine.
Ans: The numerals for eight million, sixty-nine thousand, three hundred ninety-nine is $8,069,399$.
7. Express as numeral $CDLXV$.
Ans: From the roman numeral table,
$MCMLXXXIV=1000+900+50+30+4=1984$
$CD=500-100=400$
So $CDLXV$ can be calculated as,
$CDLXV=400+50+10+5=465$
8. Express as Roman numerals $MCMLXXXIV$
$CM=1000-100=900$
So $MCMLXXXIV$ can be calculated as,
9. Which of the Roman numerals is correct?
(a) $IC$
(b) $XC$
(c) $VL$
Ans: (b) $XC$
Short Answer Questions (2 Marks)
1. Write the expanded form of $563408$.
Ans: This number has $8$ at one’s place, $0$ at tens place, $4$ at hundreds place, $3$ at thousands place, $6$ at ten thousand places and $5$ at a lakh place.
$5,63,408=5\times 100000+6\times 10000+3\times 1000+4\times 100+0\times 10+8\times 1$
$5,63,408=500000+60000+3000+400+0+8$
2. Find the difference of place values of two’s, $6$’s in $65810624$.
Ans: In $65810624$, place values of $6$ are $60000000$ and $600$ .
First value is $60000000$ and second value is $600$.
Difference $=60000000-600$
$=5,99,99,400$
3. Write the greatest and smallest $4$-digit number using $5,6,0,9$.
Ans: from the given $4$digits $5,6,0,9$
Greatest $4$-digit number is $9,650$.
Smallest $4$-digit number is $5,069$.
4. What comes after and before $10000000$?
Ans: Add one to $10,000,000$ then we can find the after count.
$1,00,00,001$ comes after $1,00,00,000$
Subtract one from $10,000,000$ then we can find the before count.
$99,99,999$ comes before $1,00,00,000$
5. Which is lesser: $85740264$ or $85610784$.
Ans: Here both numbers have the same number of digits. Further, the digits at the first two places are the same in both. Then consider moving to the next digit, that is to the digit at the lakhs place. The digit at the lakhs place is lesser in $85\underline{6}10784$ than in $85\underline{7}40264$. Therefore, $85610784$ is less than $85740264$.
Short Answer Questions (3 Marks)
1. How many $6$ digit numbers are there in all?
Ans: Total number of six-digit numbers can be calculated by subtracting smallest six-digit number from the largest six-digit number and then by adding 1 to the obtained difference.
The largest $6$ digit number is $999999$
The smallest $6$ digit number is $100000$
$\therefore $Number of all $6$ digit numbers $=\left( 999999100000 \right)+1$
2. Round off $14850$ to nearest $10$’s, $100$’s, $1000$’s place.
Ans: Round off $14850$ to nearest $10$’s, $100$’s, $1000$’s place can be done like this,
To nearest 10’s place: $14850=14,850$
To nearest 100’s place : $14850=14,900$
To nearest 1000’s place : $14850=15,000$
3. Estimate the sum $\left( 304+243 \right)$ to the nearest hundred.
Ans: Here $304$ is greater than $243$. Round off to hundreds and then find the sum.
Estimation nearest $100$’s place:
$3\underline{0}4=400$
$2\underline{4}3=200$
Estimated Sum of $\left( 304+243 \right)$ to the nearest hundred.
$\Rightarrow 300+200=500$
4. Estimate the difference of $\left( 973-368 \right)$to the nearest hundreds place.
Ans: Here $973$ is greater than $368$. Round off to hundreds and then find the difference.
Estimation nearest $100$’s place for $9\underline{7}3=1000$
Estimation nearest $100$’s place for $3\underline{6}8=400$
Estimated Difference of $\left( 973-368 \right)$ to the nearest hundreds place.
$\Rightarrow 1000-400=600$
5. Estimate product of $\left( 24\times 85 \right)$.
Ans: Here $85$ is greater than $24$. Round off them to $10$’s place then find the product.
Estimation of $24$: $10$’s place considered $=20$.
Estimation of $85$ : $10$’s place considered $=90$.
Estimated product of $\left( 24\times 85 \right)$ to the nearest $10$’s place
$\Rightarrow 20\times 90=1800$
6. Estimate quotient of $\left( 725\times 25 \right)$
Ans: Here $725$ is greater than $25$. Round off $725$ to $100$’s and $25$ to $10$’s place then find the quotient.
Estimation considering $100$’s place for $725=700$ Estimation considering $10$’s place for $25=30$
$\begin{align} & 30\overset{23}{\overline{\left){700}\right.}} \\ & \text{ }\underline{-60} \\ & \text{ 100} \\ & \text{ }\underline{-90} \\ & \text{ 10} \\ \end{align}$
Quotient $=23$
Remainder $=10$
Long Answer Questions (5 Marks)
1. Write the smallest and greatest $6$ digit numbers formed by using digits $1,0,5,7$ with repetition.
Ans: consider the given $4$ digits $1,0,5,7$ and with repetition allowed form the greatest and smallest $6$ digit numbers. For the $6$ digit, the greatest number $7$ is the first digit, whereas for the smallest number $1$ will be the first digit.
Greatest $6$ digit number with repetition $=777,510$
Smallest $6$ digit number with repetition $=100,057$
2. Arrange in Descending order $4123676,71204381,176489,3240973$
Ans: From the given numbers it’s clear that each number differs in their digit count so first count the digits.
$4123673=7$ digits
$71204381=8$ digits
$176489=6$ digits
$3240973=7$ digits
Now considering this digit counts, write the given numbers in ascending order. From the greatest number to the smallest number.
Descending order: $71204381,4123676,3240973,176489$.
3. The difference between the two numbers is $3856749$. If the smaller number is $2565638$. Find the greater number.
Ans: we know that difference is obtained by subtracting subtrahend from minuend.
Minuend $-$ Subtrahend $=$ Difference
In the problem it is given that, the difference between two numbers is $3856749$ and the smaller number is $2565638$ That means Subtrahend.
Hence, minuend $=$ Difference $+$ Subtrahend
$\Rightarrow 38,56,749+25,65,638=64,22,387$
$\therefore $ the greatest number is $64,22,387$.
4. The mass of a bag is $2kg 890g$. What is the mass of $14$ such bags?
Ans: in the problem it is given that,
Mass of a bag $=2kg 890g$.
So, to find a mass of $14$ such bags multiply $14$ with one bag weight .
$\therefore $ Mass of 14 bags $=\left( 2kg\text{ }890g \right)\times 14$
$=40kg\text{ }460g$
5. A thread of length $20m$ has been divided into $5$ pieces. What is the length of each piece?
Ans: in the problem it is given that, A thread of length $20m$ has been divided into $5$ pieces.
Total length of the thread $=20m$
Number of thread pieces $=5$
Hence length of each thread piece $\dfrac{20}{5}=4m$
6. A man had Rs. $2,08,78,560$ amounts in his bank. He withdrew Rs. $48,36,980$ in the month of January, Rs. $3,95,648$ in the month of February and Rs. $45,000$ in the month of march. What is the amount remaining in his bank account by the end of march?
Ans: In the problem it is given that,
Total amount in bank = Rs. $2,08,78,560$ Amount withdrawn in January = Rs. $48,36,980$ Amount withdrawn in February = Rs. $3,95,648$ Amount withdrawn in March = Rs. $45,000$
Amount remaining in bank account by end of march
$=2,08,78,560-48,36,980-3,95,648-45000$
$=1,56,00,932$.
Amount remaining in bank account by end of march Rs. $1,56,00,932$.
Knowing our numbers class 6 maths important questions pdf is something you need to have when trying to solve problems that might be hard for you. But don’t think about opening up the pdf side by side when you are trying to write down the answer. Also, this pdf is curated to help students who are present in class 6th. Thus, the language is quite simple with lots of jokes and engaging facts.
You can easily download the class 6 maths chapter 1 important questions in pdf format and save it in your local drive. As a result, you don’t have to be connected with the internet connection all the time to access the answers to your maths problems. The teachers at Vedantu have been in the teaching business for more than 5 years. They know every point that needs to be discussed with the kids to understand the topic better. Thus, you can trust our solved answer Pdfs without any worries.
Before we proceed to tell our students about the crucial questions, we would like to give them a little bit of description about the topics they will cover in this chapter. Given below are the main topics which students will be learning as they go through this chapter.
There are many definitions that one can look for if they ask someone what the meaning of numbers is. Well, for starters numbers are the things which are used by humans to count. For example, if you see a single butterfly so if you count in terms of number, it is 1.
Also, the number system starts from 1, and it goes to infinity there is no end to the numbers. One can go as far as they wanted. With numbers, you can count things, add different products and much more. In terms of mathematics, numbers are the building blocks of real mathematics that we study and learn today.
This is one of the new topics and mathematical functions that students get to use to find out the answer. In ascending order, one has to arrange different numbers one after the other depending on their power, which means there are 5 different numbers such as 5, 22, 48, 99, and 27. Then you put these numbers in ascending order by seeing which number is the smallest from the given number and putting it in the first place.
Here in the given example 5 is the smallest number from all the other numbers. On the other hand, 99 is the most significant number, but it’s in the fourth position, so we put it last. Now we have 22, 48 and 27. We now arrange them by choosing the smallest and the biggest, and that’s how you write the ascending order for the given numbers. The final number line will be 5,22,27,48, and 99.
The descending order is the total opposite of the ascending order. In this, you need to put the highest number in the first place and the smallest number at the end. The descending order means first comes the biggest, and from there, the numbers will only become small, and the last digit will be the smallest from the whole set of numbers.
For example, there are 5 numbers present in the box which are 22, 48, 99, 5 and 27. So if a student needs to arrange them, he needs to put the highest number in front and the smallest number at the back or end. So now the number line will look like this. 99, 22, 48, 27 and 5. Just like that, we use the descending order again, and this time we get 99, 48, 27, 22 and 5. This is the descending order of the example.
A place value defines the positional notation of a digit’s position. This might sound complicated, but it’s nothing to be worried about. Let's clear it by taking an example. Take a big number like 53210. Here let’s try to find out the place value for each single number present.
0 = zero place
1 = one’s place
2 = two’s place
3 = hundered’s place.
4 = thousand’s place
5 = ten thousand’s place.
The place value is one of the most important concepts as it introduces you to the currency system, and there are two different place values, but in this chapter, we are only discussing Indian place value system.
Now that you have revised the topics and mathematical terms of class 6 maths chapter 1 extra questions. Let’s get things going and solve these questions which are written down below. These questions are specially curated by Vedantu’s experienced teacher to test out how much did the student can grasp from the chapter.
Q1: Write the biggest three-digit number
Q2: Write the greatest four-digit number which doesn’t change even if we reverse the digit which is placed on one’s and second’s place.
Q3: What must be subtracted to 203 to get a number whose digits are reversed of the given number?
Q4: Write the greatest five-digit number using the digits 7, 9 and 1.
Q5: If the capacity of a water tank is 30 litres, then what will be the capacity of the water tank in millimetres?
Q6: What will be the successor of the greatest 5 digit number?
Q7: What is the place value of the digit 5 in 5431?
Q8: From the given two numbers 24567, and 99871, which one is the biggest number and by how much?
Q9: Write down the following numbers in descending order 63,854, 63,584, 65,348, 68,543, 64,835
Q10: Find out the estimation of 25,148 + 7394 + 9343 + 752.
These are just ten questions you can quickly solve and find their answer on your own if you are stuck somewhere. Follow our step by step solving of the other examples which are present in Pdf.
We know a lot of times students think about not solving many questions from a single chapter once they understand the topic. But let Vedantu give you some advice by showing you the benefits of solving more and more problems from the same chapter.
Clears Out Your Doubts:- When you solve more questions you will gain confidence over the topic which could be new to you.
Math’s is All About Solving:- The more you solve, the better you learn, meaning when you solve tons of problems you will be well prepared to solve unseen questions which might come in your exams.
Develops Mathematical Power:- It allows students to test out their brains and use their mathematical knowledge to solve both theoretical and real-world problems.
Maths Gets You Prepared:- Lastly, solving problems will develop a student’s brain to adapt to new changes and new topics which they haven’t encountered yet in their syllabus.
So there you go, now students, you need to start solving the questions which are present on this page. In addition to this, make sure you complete the worksheets which are located at the end of the chapter as it will help you by giving you the variety of the questions from the same chapter.
These important questions class 6 maths chapter 1 will help you in making a strong base for your upcoming classes where the mathematical topics start to become a bit more complicated and hard to understand. It’s better if you start learning now and practice solving extra questions with full focus and determination.
CBSE Class 6 Maths Study Materials |
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Q1. What do you learn from Chapter 1-Our Numbers of Class 6 Maths?
Ans: Knowing our numbers is the first Chapter in Class 6 maths. In this chapter, students will learn the concepts of the number system. Students will learn how to write numbers in words and how to write words in numerals. There are many other topics covered in Chapter 1 of Class 6 Maths. Students can find all NCERT solutions for Chapter 1 of Class 6 maths on Vedantu app and website free of cost. They can practice NCERT solutions to understand the concepts and score high marks in Class 6 Maths.
Q2. How many exercises are there in Chapter 1 of Class 6 Maths?
Ans: In Chapter 1 of Class 6 Maths, there are five exercises. Each exercise is further divided into different sections. Students will learn about different concepts on numbers. In the first exercise, students will learn about the basics of numbers, in the second exercise students will learn about the concept of comparing numbers, in the third exercise students will study about large numbers, in the fourth exercise students will study the use of brackets and the last exercise is based on roman numbers.
Q3. How should I understand all concepts of Chapter 1 of Class 6 Maths?
Ans: Students can understand the concepts of Chapter 1 by practising important questions given on Vedantu. Students can practice all-important questions available on Vedantu for scoring high marks in Class 6 Maths. All NCERT important questions are given along with solutions on Vedantu website and mobile app. The solutions are prepared by expert teachers who help students to understand all concepts of Class 6 Maths quickly. Students can practice questions given in all exercises to understand the basics of the chapter.
Q4. Is Chapter 1 of Class 6 Maths important for exams?
Ans: Chapter 1 based on numbers is important for exams. Students learn the basic concepts of numbers in the first chapter. They will learn how to write numbers in the expanded form, roman numbers, writing numbers in words, etc, in the first chapter. Therefore, it is an important chapter because students can get short questions from this chapter. Students can practice from the NCERT Solutions to learn the concepts of this chapter better.
Q5. What is the benefit of studying important questions of Chapter 1 of Class 6 Maths?
Ans: Students should study and practice the important questions of Chapter 1 of Class 6 Maths for understanding the basic concepts given in the first chapter. They can understand all the formulas and ways to solve the questions by practising important questions. Important questions available on Vedantu are chosen by expert professionals by keeping exams in their minds and can help students practice all concepts and get good marks. For important questions of Chapter 1 of Class 6 Maths, visit Vedantu website or mobile app and download the PDF free of cost.
Cbse study materials.
NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers help the students who aspire to obtain a good academic score in exams. Experts at BYJU’S designed these solutions to boost the confidence of students by assisting them in understanding the concepts covered in this chapter. NCERT Solutions for Class 6 contains the methods to solve problems present in the textbook quickly and easily. These materials are prepared based on the Class 6 NCERT syllabus, taking the types of questions asked in the NCERT textbook into consideration.
Download most important questions for class 6 maths chapter 1 – knowing our numbers.
Utilising the NCERT Solutions will aid students in understanding the key concepts effortlessly. Further, all the solutions are in accordance with the latest CBSE guidelines and marking schemes. Download the NCERT solutions of this chapter in PDF format from the link attached below to kickstart preparations.
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Exercise 1.1 PAGE NO: 12
1. Fill in the blanks:
(a) 1 lakh = ………….. ten thousand.
(b) 1 million = ………… hundred thousand.
(c) 1 crore = ………… ten lakhs.
(d) 1 crore = ………… million.
(e) 1 million = ………… lakhs.
(a) 1 lakh = 10 ten thousand
(b) 1 million = 10 hundred thousand
= 10,00,000
(c) 1 crore = 10 ten lakhs
= 1,00,00,000
(d) 1 crore = 10 million
(e) 1 million = 10 lakhs
= 1,000,000
2. Place commas correctly and write the numerals:
(a) Seventy three lakh seventy five thousand three hundred seven
(b) Nine crore five lakh forty one
(c) Seven crore fifty two lakh twenty one thousand three hundred two
(d) Fifty eight million four hundred twenty three thousand two hundred two
(e) Twenty three lakh thirty thousand ten
(a) The numeral of seventy three lakh seventy five thousand three hundred seven is 73,75,307
(b) The numeral of nine crore five lakh forty one is 9,05,00,041
(c) The numeral of seven crore fifty two lakh twenty one thousand three hundred two is 7,52,21,302
(d) The numeral of fifty eight million four hundred twenty three thousand two hundred two is 5,84,23,202
(e) The numeral of twenty three lakh thirty thousand ten is 23,30,010
3. Insert commas suitably and write the names according to the Indian System of Numeration:
(a) 87595762 (b) 8546283 (c) 99900046 (d) 98432701
(a) 8,75,95,762 – Eight crore seventy five lakh ninety five thousand seven hundred sixty two
(b) 85,46,283 – Eighty five lakh forty six thousand two hundred eighty three
(c) 9,99,00,046 – Nine crore ninety nine lakh forty six
(d) 9,84,32,701 – Nine crore eighty four lakh thirty two thousand seven hundred one
4. Insert commas suitably and write the names according to the International System of Numeration:
(a) 78921092 (b) 7452283 (c) 99985102 (d) 48049831
(a) 78,921,092 – Seventy eight million nine hundred twenty one thousand ninety two
(b) 7,452,283 – Seven million four hundred fifty-two thousand two hundred eighty three
(c) 99,985,102 – Ninety-nine million nine hundred eighty five thousand one hundred two
(d) 48,049,831 – Forty-eight million forty-nine thousand eight hundred thirty-one
Exercise 1.2 PAGE NO: 16
1. A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094, 1812, 2050 and 2751. Find the total number of tickets sold on all four days.
Number of tickets sold on 1st day = 1094
Number of tickets sold on 2nd day = 1812
Number of tickets sold on 3rd day = 2050
Number of tickets sold on 4th day = 2751
Hence, the total number of tickets sold on all four days = 1094 + 1812 + 2050 + 2751 = 7707 tickets
2. Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10,000 runs. How many more runs does he need?
Shekhar scored = 6980 runs
He wants to complete = 10000 runs
Runs needed to score more = 10000 – 6980 = 3020
Hence, he needs 3020 more runs to score
3. In an election, the successful candidate registered 5,77,500 votes, and his nearest rival secured 3,48,700 votes. By what margin did the successful candidate win the election?
No. of votes secured by the successful candidate = 577500
No. of votes secured by his rival = 348700
Margin by which he won the election = 577500 – 348700 = 228800 votes
∴ The successful candidate won the election by 228800 votes
4. Kirti bookstore sold books worth Rs 2,85,891 in the first week of June and books worth Rs 4,00,768 in the second week of the month. How much was the sale for the two weeks together? In which week was the sale greater and by how much?
Price of books sold in the first week of June = Rs 285891
Price of books sold in the second week of June = Rs 400768
No. of books sold in both weeks together = Rs 285891 + Rs 400768 = Rs 686659
The sale of books is the highest in the second week.
Difference in the sale in both weeks = Rs 400768 – Rs 285891 = Rs 114877
∴ Sale in the second week was greater by Rs 114877 than in the first week.
5. Find the difference between the greatest and the least 5-digit number that can be written using the digits 6, 2, 7, 4, and 3 each only once.
Digits given are 6, 2, 7, 4, 3
Greatest 5-digit number = 76432
Least 5-digit number = 23467
Difference between the two numbers = 76432 – 23467 = 52965
∴ The difference between the two numbers is 52965.
6. A machine, on average, manufactures 2,825 screws a day. How many screws did it produce in the month of January 2006?
Number of screws manufactured in a day = 2825
Since January month has 31 days,
The number of screws manufactured in January = 31 × 2825 = 87575
Hence, the machine produced 87575 screws in the month of January 2006.
7. A merchant had Rs 78,592 with her. She placed an order for purchasing 40 radio sets at Rs 1200 each. How much money will remain with her after the purchase?
Total money the merchant had = Rs 78592
The number of radio sets she placed an order for purchasing = 40 radio sets
Cost of each radio set = Rs 1200
So, cost of 40 radio sets = Rs 1200 × 40 = Rs 48000
Money left with the merchant = Rs 78592 – Rs 48000 = Rs 30592
Hence, money left with the merchant after purchasing radio sets is Rs 30592.
8. A student multiplied 7236 by 65 instead of multiplying by 56. By how much was his answer greater than the correct answer?
Difference between 65 and 56, i.e. (65 – 56) = 9
The difference between the correct and incorrect answer = 7236 × 9 = 65124
Hence, by 65124, the answer was greater than the correct answer.
9. To stitch a shirt, 2 m 15 cm cloth is needed. Out of 40 m cloth, how many shirts can be stitched and how much cloth will remain?
The total length of the cloth = 40 m
= 40 × 100 cm = 4000 cm
Cloth required to stitch one shirt = 2 m 15 cm
= 2 × 100 + 15 cm = 215 cm
Number of shirts that can be stitched out of 4000 cm = 4000/215 = 18 shirts
Hence, 18 shirts can be stitched out of 40 m, and 1 m 30 cm of cloth is left.
10. Medicine is packed in boxes, each weighing 4 kg 500g. How many such boxes can be loaded in a van which cannot carry beyond 800 kg?
Weight of one box = 4 kg 500 g = 4 × 1000 + 500
Maximum weight carried by the van = 800 kg = 800 × 1000
Hence, the number of boxes that can be loaded in the van = 800000/4500 = 177 boxes
11. The distance between the school and a student’s house is 1 km 875 m. Every day, she walks both ways. Find the total distance covered by her in six days.
Distance covered between the school and her house = 1 km 875 m = 1000 + 875 = 1875 m
Since the student walks both ways,
The distance travelled by the student in one day = 2 × 1875 = 3750 m
Distance travelled by the student in 6 days = 3750 m × 6 = 22500 m = 22 km 500 m
∴ The total distance covered by the student in six days is 22 km and 500 m.
12. A vessel has 4 litres and 500 ml of curd. In how many glasses, each of 25 ml capacity, can it be filled?
Quantity of curd in the vessel = 4 l 500 ml = 4 × 1000 + 500 = 4500 ml
Capacity of 1 glass = 25 ml
∴ Number of glasses that can be filled with curd = 4500 / 25 = 180 glasses
Hence, 180 glasses can be filled with curd.
Exercise 1.3 Page NO: 23
1. Estimate each of the following using the general rule:
(a) 730 + 998 (b) 796 – 314 (c) 12904 + 2888 (d) 28292 – 21496
Make ten more such examples of addition, subtraction and estimation of their outcome.
(a) 730 + 998
Round off to hundreds
730 rounds off to 700
998 rounds off to 1000
Hence, 730 + 998 = 700 + 1000 = 1700
(b) 796 – 314
796 rounds off to 800
314 rounds off to 300
Hence, 796 – 314 = 800 – 300 = 500
(c) 12904 + 2888
Round off to thousands
12904 rounds off to 13000
2888 rounds off to 3000
Hence, 12904 + 2888 = 13000 + 3000 = 16000
(d) 28292 – 21496
28292 round off to 28000
21496 round off to 21000
Hence, 28292 – 21496 = 28000 – 21000 = 7000
Ten more such examples are
(i) 330 + 280 = 300 + 300 = 600
(ii) 3937 + 5990 = 4000 + 6000 = 10000
(iii) 6392 – 3772 = 6000 – 4000 = 2000
(iv) 5440 – 2972 = 5000 – 3000 = 2000
(v) 2175 + 1206 = 2000 + 1000 = 3000
(vi) 1110 – 1292 = 1000 – 1000 = 0
(vii) 910 + 575 = 900 + 600 = 1500
(viii) 6400 – 4900 = 6000 – 5000 = 1000
(ix) 3731 + 1300 = 4000 + 1000 = 5000
(x) 6485 – 4319 = 6000 – 4000 = 2000
2. Give a rough estimate (by rounding off to the nearest hundreds) and also a closer estimate (by rounding off to the nearest tens):
(a) 439 + 334 + 4317 (b) 108734 – 47599 (c) 8325 – 491 (d) 489348 – 48365
Make four more such examples.
(a) 439 + 334 + 4317
Rounding off to the nearest hundreds
439 + 334 + 4317 = 400 + 300 + 4300
Rounding off to the nearest tens
439 + 334 + 4317 = 440 + 330 + 4320
(b) 108734 – 47599
108734 – 47599 = 108700 – 47600
108734 – 47599 = 108730 – 47600
(c) 8325 – 491
8325 – 491 = 8300 – 500
8325 – 491 = 8330 – 490
(d) 489348 – 48365
489348 – 48365 = 489300 – 48400
489348 – 48365 = 489350 – 48370
Four more examples are as follows:
(i) 4853 + 662
4853 + 662 = 4800 + 700
4853 + 662 = 4850 + 660
(ii) 775 – 390
775 – 390 = 800 – 400
775 – 390 = 780 – 400
(iii) 6375 – 2875
6375 – 2875 = 6400 – 2900
6375 – 2875 = 6380 – 2880
(iv) 8246 – 6312
8246 – 6312 = 8200 – 6300
8246 – 6312 = 8240 – 6310
3. Estimate the following products using the general rule:
(a) 578 × 161
(b) 5281 × 3491
(c) 1291 × 592
(d) 9250 × 29
Rounding off by general rule
578 and 161 rounded off to 600 and 200, respectively
____________
_____________
5281 and 3491 rounded off to 5000 and 3500, respectively
1291 and 592 rounded off to 1300 and 600, respectively
______________
9250 and 29 rounded off to 9000 and 30, respectively
Disclaimer:
Dropped Topics – 1.3.1 Estimation, 1.3.2 Estimating to the nearest tens by rounding off, 1.3.3 Estimating to the nearest hundreds by rounding off, 1.3.4 Estimating to the nearest thousands by rounding off, 1.3.5 Estimating outcomes of number situations, 1.3.6 To estimate sum or difference, 1.3.7 To estimate products, 1.4 Using brackets, 1.4.1 Expanding brackets, 1.5 Roman numerals.
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Ch – 1 Knowing our Numbers
Match the following-
Column I | Column II |
---|---|
a. Estimation | p. International System |
b. Billion, Million | q. Rough Calculation |
c. Crore | r. 90,030 |
d. Nine Thousand Thirty | s. Indian System |
Fill in the blanks:
State whether the following statements are true or false.
Number system, practice now, number system and its operations, knowing our numbers, self test-1.
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Online Maths Lessons and Exercises
by Sanjusha · July 20, 2020
CBSE CLASS 6 MATHEMATICS Knowing Our Numbers – Chapter1 Extra Questions for Practice – Short Answer Type Questions
Answer the following questions (2 marks):
1. Put commas suitably and write the number name in International System of Numeration: 70002509.
2. Write the smallest and greatest 5 digit numbers having 4 in the hundreds place, without repeating any digit.
3. Find the product of smallest 3 digit number and greatest 4 digit number?
4. Estimate i) 423 + 789 to the nearest tens. ii) 852 – 689 to the nearest hundreds.
5. Write the numeral for: i) Nine crore eight lakh five hundred. ii) Seven million six hundred thirty three thousand four hundred fifteen.
6. Find the difference between the greatest and smallest 4 digit number that can be written using the digits 6, 2, 7, 3 each only once.
7. How many hundred thousand makes one million?
8. Write the following in Roman Numerals: i) 94 ii) 198
9. Give the Hindu-Arabic numeral for: i) XCVIII ii) XLIII
10. Find the difference between the place value and face value of 8 in 7894.
1. 70,002,509. Number name: Seventy million two thousand five hundred nine.
2. Smallest number is 10423 and greatest number is 98476.
3. Smallest 3 digit number is 100 and greatest 4 digit number is 9999. Product = 9999 x 100 = 999900.
4. i) 423 rounds off to 420. 789 rounds off to 790. Estimated sum = 420 + 790 = 1210. ii) 852 rounds off to 900. 689 rounds off to 700. Estimated difference = 900 – 700 = 200.
5. i) 9,08,00,500 ii) 7,633,415.
6. Greatest 4 digit number is 9999 and smallest 4 digit number is 1000. Difference = 9999 – 1000 = 8999.
7. 10 hundred thousand makes one million.
8. i) 94 = XCIV ii) 198 = CXCVIII.
9. i) 98 ii) 43
10. Place value of 8 in 7894 is 800 and face value of 8 is 8 itself. Difference = 800 – 8 = 792.
Tags: CBSE Class 6 Maths Class 6 maths chapter1 Extra questions for practice Knowing our numbers Short answer type questions
Cbse class 6 mathematics worksheets/part 4/half yearly examination.
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good but can you also add very short answer type questions and long answer type questions
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NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers will help the students take their understanding of numbers a bit further and explore topics like shifting digits, expanding brackets, roman numerals, estimating sum or difference, products, outcomes of number situations, and many more. This chapter will also help the students revise all the operations on numbers like multiplication , addition , subtraction , and division covered in the previous classes. Presented below is an in-depth analysis of Class 6 Maths NCERT Solutions Chapter 1.
These solutions will help the students understand large numbers through real-life examples while also exploring their unit conversions. They will also get to learn about the International and Indian systems of numeration along with an introduction to the concept of roman numerals. Let us now take a deeper look at the different sub-topics covered in NCERT Solutions Class 6 Maths Chapter 1 and also you can find some of these in the exercises given below.
NCERT Solutions Class 6 Maths Chapter 1 Knowing Our Numbers contains all the important questions, images, explanations, and formulas covered in the chapter. These solutions are aimed at helping the students understand and solve complex concepts such as the use of commas in larger numbers. Commas are used to mark thousands, lakhs, and crores. Let us do a detailed exercise-wise overview of this chapter using the PDF links given below :
NCERT Class 6 Maths Chapter 1 Download PDF
Students must have already studied the formation of numbers in the previous classes. In this chapter, they will be introduced to the concept of arranging numbers in ascending as well as in descending order and shifting the digits to form new numbers. All these ideas are explained along with real-life examples in the NCERT Solutions Class 6 Maths Chapter 1 Knowing Our Numbers.
☛ Download Class 6 Maths Chapter 1 NCERT Book
Topics Covered: The important topics covered under Class 6 maths NCERT Solutions Chapter 1 are natural numbers , comparison of numbers, place value of a digit, estimation of the numbers, roman numerals , and importance of brackets. Questions related to all these topics must be practiced regularly to score excellent marks in the exams.
Total Questions: Class 6 Maths Chapter 1 Knowing Our Numbers has a total of 21 well-researched questions out of which 12 are straightforward, 3 are of moderate level, and 6 are complex level problems.
NCERT solutions class 6 maths chapter 1 does not cover any formulas . However, there are some pointers that the students must remember while solving problems from this chapter. These pointers will help them avoid mistakes while giving a crystal clear understanding of the topics covered in this chapter. Let us now go through these pointers one by one :
CBSE Important Questions for Class 6 Maths Chapter 1 Exercise 1.1 |
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CBSE Important Questions for Class 6 Maths Chapter 1 Exercise 1.2 |
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CBSE Important Questions for Class 6 Maths Chapter 1 Exercise 1.3 |
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Why are ncert solutions class 6 maths chapter 1 important.
NCERT Solutions Class 6 Maths Chapter 1 will help kids identify pain points and find ways to solve questions in an efficient manner. They focus on some of the fundamental concepts that act as a building block for a kid’s mathematical journey. Topics such as estimation have practical applications in our daily life as it gives an idea of the quantity. Thus these solutions are extremely important for students considering their utility in everyday life.
All the questions in NCERT Solutions are curated by experts covering a range of topics. NCERT Solutions for Class 6 Maths Chapter 1 will help you explore all the topics in detail by solving a range of problems. Thus practicing all the questions of this chapter is important for a strong mathematical foundation.
NCERT Solutions Class 6 Maths Chapter 1 covers a range of essential topics such as estimating numbers, use of commas, place value, expanding brackets, and roman numerals. Questions related to all these topics are explained in a step-wise manner in the NCERT solutions.
There are a total of 21 sums in the NCERT Solutions Class 6 Maths Chapter 1 Knowing Your Numbers. These questions are distributed in 3 exercises. Out of 21 questions, 10 are easy sums, 5 are moderately difficult problems, while 6 are complex sums that need brainstorming.
In order to effectively utilize the NCERT Solutions Class 6 Maths Chapter 1 students must go through the detailed solutions of all the questions, explore the chapter summary, and theory of the chapter. Students must give adequate time to all the exercises and solve questions in a step-wise manner.
NCERT Solutions Class 6 Maths Chapter 1 Knowing Your Numbers will help you revise the previous concepts from earlier classes like place values, whole numbers, number system, etc. Apart from that, this chapter will help you understand the applications of interesting concepts in your day-to-day life.
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Comparing numbers.
RS Aggarwal Solutions for Class 6 Math Chapter 1 Knowing Our Numbers are provided here with simple step-by-step explanations. These solutions for Knowing Our Numbers are extremely popular among class 6 students for Math Knowing Our Numbers Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the RS Aggarwal Book of class 6 Math Chapter 1 are provided here for you for free. You will also love the ad-free experience on Meritnation’s RS Aggarwal Solutions. All RS Aggarwal Solutions for class 6 Math are prepared by experts and are 100% accurate.
Question 1:.
Fill in the blanks:
(a). 1 lakh = _________ ten thousand.
(b). 1 million = _________ hundred thousand.
(c). 1 crore = _________ ten lakh.
(d). 1 crore = _________ million.
(e). 1 million = _________ lakh.
(1 lakh = 1,00,000 and ten thousand = 10,000)
(1 million = 1,000,000 and 1 hundred thousand = 1, 00,000)
(1 crore = 1,00,00,000 and Ten lakh = 10,00,000)
(1 crore = 1,00,00,000 and 1 million = 1,000,000)
(1 million = 1,000,000 and 1 lakh = 1,00,000)
Place commas correctly and write the numerals:
(a). Seventy three lakh seventy five thousand three hundred seven.
(b). Nine crore five lakh forty one.
(c). Seven crore fifty two lakh twenty one thousand three hundred two.
(d). Fifty eight million four hundred twenty three thousand two hundred two.
(e). Twenty three lakh thirty thousand ten.
(a) 73,75,307
(b) 9,05,00,041
(c) 7,52,21,302
(d) 58,423,202
(e) 23,30,010
Insert commas suitably and write the names according to Indian System of Numeration:
(a). 87595762 (b). 8546283
(c). 99900046 (d). 98432701
(a) 8,75,95,762
Eight crore seventy five lakh ninety five thousand seven hundred sixty two
(b) 85,46,283
Eighty five lakh forty six thousand two hundred eighty three
(c) 9,99,00,046
Nine crore ninety nine lakh forty six
(d) 9,84,32,701
Nine crore eighty four lakh thirty two thousand seven hundred one
NCERT Solution for Class 6 math - Knowing Our Numbers 12 , Question 3
Insert commas suitably and write the names according to International System of Numeration:
(a). 78921092 (b). 7452283
(c). 99985102 (d). 48049831
(a) 78,921,092
Seventy eight million nine hundred twenty one thousand ninety two
(b) 7,452,283
Seven million four hundred fifty two thousand two hundred eighty three
(c) 99,985,102
Ninety nine million nine hundred eighty five thousand one hundred two
(d) 48, 049,831
Forty eight million forty nine thousand eight hundred thirty one
NCERT Solution for Class 6 math - Knowing Our Numbers 12 , Question 4
A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third, and final day was respectively 1094, 1812, 2050, and 2751. Find the total number of tickets sold on all the four days.
Tickets sold on 1 st day = 1094
Tickets sold on 2 nd day = 1812
Tickets sold on 3 rd day = 2050
Tickets sold on 4 th day = 2751
Total tickets sold = 1094 + 1812 + 2050 + 2751
∴ Total tickets sold = 7,707
Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10, 000 runs. How many more runs does he need?
Runs scored so far = 6980
Runs Shekhar wants to score = 10,000
More runs required = 10,000 − 6980
∴ Shekhar requires 3,020 more runs.
NCERT Solution for Class 6 math - Knowing Our Numbers 16 , Question 2
In an election, the successful candidate registered 5, 77, 500 votes and his nearest rival secured 3, 48, 700 votes. By what margin did the successful candidate win the election?
Votes secured by successful candidate = 5,77,500
Votes secured by rival = 3,48,700
Margin = 5,77,500 − 3,48,700
∴ Margin = 2,28,800
Kirti bookstore sold books worth Rs 2,85,891 in the first week of June and books worth Rs 4,00,768 in the second week of the month. How much was the sale for the two weeks together? In which week was the sale greater and by how much?
Value of Books sold in 1 st week = Rs 2,85,891
Value of books sold in 2 nd week = Rs 4,00,768
Total sale = Sale in 1 st week + Sale in 2 nd week
= 2,85,891 + 4,00,768
The sale for the two weeks together was 6,86,659.
Since 4,00,768 > 2,85,891, sale in 2 nd week was greater than 1 st week.
∴ The sale in 2 nd week was larger than the sale in 1 st week by Rs 1,14,877.
NCERT Solution for Class 6 math - Knowing Our Numbers 16 , Question 4
Question 5:.
Find the difference between the greatest and the least number that can be written using the digits 6, 2, 7, 4, 3 each only once.
Greatest number = 76432
Smallest number = 23467
Difference = 76432 − 23467
Therefore, the difference between the greatest and the least number that can be written using the digits 6, 2, 7, 4, 3 each only once is 52,965.
A machine, on an average, manufactures 2,825 screws a day. How many screws did it produce in the month of January 2006?
Screws produced in one day = 2,825
Days in January = 31
Screws produced in 31 days = 2825 × 31
Therefore, screws produced during Jan, 06 = 87,575
A merchant had Rs 78,592 with her. She placed an order for purchasing 40 radio sets at Rs 1200 each. How much money will remain with her after the purchase?
Cost of one radio set = Rs 1200
Cost of 40 radio sets = 1200 × 40 = Rs 48000
Money with Merchant = Rs 78,592
Money spent = Rs 48,000
Money left = 78592 − 48000
Therefore, Rs 30,592 will remain with her after the purchase.
A student multiplied 7236 by 65 instead of multiplying by 56. By how much was his answer greater than the correct answer? (Hint: Do you need to do both the multiplications?)
Difference between 65 and 56 = 9
Difference in the answer = 7236 × 9
Therefore, his answer was greater than the correct answer by 65,124.
To stitch a shirt, 2m 15 cm cloth is needed. Out of 40 m cloth, how many shirts can be stitched and how much cloth will remain? (Hint: convert data in cm.)
2 m 15 cm = 215 cm (1 m = 100 cm)
40 m = 40 × 100
Cloth required for one shirt = 215 cm
Number of shirts that can be stitched out of 4000 cm = 4000 ÷ 215
Therefore, 18 shirts can be made. 130 cm, i.e. 1 m 30 cm, cloth will remain.
Medicine is packed in boxes, each weighing 4 kg 500 g. How many such boxes can be loaded in a van which cannot carry beyond 800 kg?
1 kg = 1000 g
4 kg 500 g = 4500 g
800 kg = 800 × 1000 = 800000 g
Number of boxes that can be loaded in the van = 800000 ÷ 4500
Hence, 177 boxes at maximum can be loaded in the van.
NCERT Solution for Class 6 math - Knowing Our Numbers 17 , Question 10
The distance between the school and the house of a student’s house is 1 km 875 m. Everyday she walks both ways. Find the total distance covered by her in six days.
Distance between school and house = 1 km 875 m
Now, 1 km = 1000 m
1 km 875 m = 1875 m
Distance covered each day = 1875 × 2 = 3750 m
Distance covered in 6 days = 3750 × 6
Therefore, distance covered in 6 days = 22,500 m
= 22.5 km or 22 km 500 m
A vessel has 4 litres and 500 ml of curd. In how many glasses, each of 25 ml capacity, can it be filled?
Capacity of vessel = 4 l 500 ml
= 4500 ml (1 l = 1000 ml)
Capacity of a glass = 25 ml
Number of glasses that can be filled = 4500 ÷ 25
∴ 180 glasses can be filled.
NCERT Solution for Class 6 math - Knowing Our Numbers 17 , Question 12
Estimate each of the following using general rule:
(a) 730 + 998 (b) 796 − 314 (c) 12, 904 + 2, 888
(d) 28, 292 − 21, 496
Make ten more such examples of addition, subtraction and estimation of their outcome.
(a) 730 + 998
By rounding off to hundreds, 730 rounds off to 700 and 998 rounds off to 1000.
(b) 796 − 314
By rounding off to hundreds, 796 rounds off to 800 and 314 rounds off to 300.
(c) 12904 + 2822
By rounding off to thousands, 12904 rounds off to 13000 and 2822 rounds off to 3000.
(d) 28,296 − 21,496
By rounding off to nearest thousands, 28296 rounds off to 28000 and 21496 rounds off to 21000.
Give a rough estimate (by rounding off to nearest hundreds) and also a closer estimate (by rounding off to nearest tens):
(a) 439 + 334 + 4, 317 (b) 1,08, 734 − 47, 599 (c) 8325 − 491
(d) 4, 89, 348 − 48, 365
Make four more such examples.
(a) 439 + 334 + 4317
Rounding off to nearest hundreds, 439, 334, and 4317 may be rounded off to 400, 300, and 4300 respectively.
Rounding off to nearest tens, 439, 334, and 4317 may be rounded off to 440, 330, and 4320 respectively.
(b) 1,08,734 − 47,599
Rounding off to hundreds, 1,08,734 and 47,599 may be rounded off to 1,08,700 and 47,600 respectively.
Rounding off to tens, 1,08,734 and 47,599 may be rounded off to 1,08,730 and 47,600 respectively.
(c) 8325 − 491
Rounding off to hundreds, 8325 and 491 may be rounded off to 8300 and 500 respectively.
Rounding off to tens, 8325 and 491 may be rounded off to 8330 and 490 respectively.
(d) 4,89,348 − 48,365
Rounding off to hundreds, 489348 and 48365 may be rounded off to 489300 and 48400 respectively.
Rounding off to tens, 489348 and 48365 may be rounded off to 489350 and 48370 respectively.
Estimate the following products using general rule:
(a) 578 Ã 161 (b) 5281 Ã 3491
(c) 1291 Ã 592 (d) 9250 Ã 29
(a) 578 Ã 161
Rounding off by general rule, 598 and 161 may be rounded off to 600 and 200 respectively.
(b) 5281 Ã 3491
Rounding off by general rule, 5281 and 3491 may be rounded off to 5000 and 3000 respectively.
(c) 1291 Ã 592
Rounding off by general rule, 1291 and 592 may be rounded off to 1000 and 600 respectively.
(d) 9250 Ã 29
Rounding off by general rule, 9250 and 29 may be rounded off to 9000 and 30 respectively.
View NCERT Solutions for all chapters of Class 6
How many exercises in chapter 1 knowing our numbers, how to compare numbers, what is international numeration system, contact form.
Free mcq test, table of content, knowing our numbers test - 29.
Duration: 10 Mins
Maximum Marks: 10
Read the following instructions carefully.
1. The test contains 10 total questions.
2. Each question has 4 options out of which only one is correct .
3. You have to finish the test in 10 minutes.
4. You will be awarded 1 mark for each correct answer.
5. You can view your Score & Rank after submitting the test.
6. Check detailed Solution with explanation after submitting the test.
7. Rank is calculated on the basis of Marks Scored & Time
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The Knowing our Numbers MCQ are those types of questions which can create impact on the preparation level. As the multiple choice questions are designed in such a way that tests a student's memorisation skills, accordingly students can score well in the chapter Knowing our Numbers and can improvise their preparation level.
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Case Study Questions for Class 6 Maths Chapter 1 Knowing Our Numbers Here in this article, we are providing case study questions for class 6 maths. Here you will find case study questions for Class 6 Maths Chapter 1 Chapter 1 Knowing Our Numbers. Knowing Our Numbers Case Study Questions Case Study Question 1: The … Continue reading Case Study Questions for Class 6 Maths Chapter 1 Knowing Our ...
CBSE Class 6 Mathematics Knowing our Numbers Extra Questions. myCBSEguide has just released Chapter Wise Question Answers for class 6 Maths. There chapter wise Practice Questions with complete solutions are available for download in myCBSEguide website and mobile app. These Extra Questions with solution are prepared by our team of expert teachers who are teaching grade in CBSE schools for years.
Section E - Remaining Multiple Choice Questions (2 marks each) Choose the correct option and write the corresponding alphabet. Q: What is the place value of the digit 7 in the number 7,305?
Knowing Our Numbers Class 6 Extra Questions Maths Chapter 1 Extra Questions for Class 6 Maths Chapter 1 Knowing Our Numbers Knowing Our Numbers Class 6 Extra Questions Very Short Answer Type Question 1. Write the smallest three digit number whose value does not change on reversing its digits. Solution: The required number is 101. […]
Class 6 Maths Chapter 1 Important Questions - Knowing Our Numbers. Maths is an important subject we study in school. In Class 6, students will learn the basics of the subject, which will be needed in higher classes.
Get chapter-wise important questions for CBSE Class 6 Maths Chapter 1 - Knowing Our Numbers with answers on Vedantu. Download the PDF for free and revise these important questions for CBSE exam 2024-25.
RD Sharma Solutions for Class 6 Chapter 1 Knowing Our Numbers contains problems which are purely based on making the students understand the concept of numbers.
Get NCERT Solutions Class 6 Maths Chapter 1, Knowing Our Numbers. Download Free PDFs of NCERT Class 6 Maths Solutions Chapter 1 Knowing Our Numbers with examples, tips etc.
Updated for new NCERT Book.. Get NCERT Solutions of Chapter 1 Class 6 Knowing our Numbers with Videos of all questions. All exercise questions and examples are solved with step-by-step answers. In this chapter, we will. First revise our concepts of Place Value; Learn about Indian Number System and International Number System; Then, we learn how to compare large numbers
This section on Competency Based Questions has been incorporated in the curriculum in view of the National Education Policy (NEP) 2020. It includes Multiple Choice Questions, Case-based Questions, Assertion-Reasoning Questions, and even Source-Based Questions to help the students undergo an intelligent preparation process.
Important Questions for CBSE Class 6 Maths Chapter 1 - Knowing Our Numbers solved by our expert teachers for academic year 2022-23. These solutions are compliant with the latest edition books, CBSE syllabus and NCERT guidelines. Download PDFs for free at CoolGyan.Org
Practice mathematics questions for 6th class on knowing our numbers. Free question bank with answers and explanations.
5. Write the numeral for: i) Nine crore eight lakh five hundred. ii) Seven million six hundred thirty three thousand four hundred fifteen. 6. Find the difference between the greatest and smallest 4 digit number that can be written using the digits 6, 2, 7, 3 each only once.
NCERT Solutions Class 6 Maths Chapter 1 Knowing Our Numbers. NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers will help the students take their understanding of numbers a bit further and explore topics like shifting digits, expanding brackets, roman numerals, estimating sum or difference, products, outcomes of number situations, and many more.
Download Knowing our Numbers Class 6 Mind Map, Notes, MCQ and extra questions and answers from NCERT Class 6 Maths Chapter 1.
Learn for free about math, art, computer programming, economics, physics, chemistry, biology, medicine, finance, history, and more. Khan Academy is a nonprofit with the mission of providing a free, world-class education for anyone, anywhere.
RS Aggarwal Solutions for Class 6 Math Chapter 1 Knowing Our Numbers are provided here with simple step-by-step explanations. These solutions for Knowing Our Numbers are extremely popular among class 6 students for Math Knowing Our Numbers Solutions come handy for quickly completing your homework and preparing for exams.
These NCERT Solutions for Class 6 will develop you understanding of the chapter and help in gaining good marks in the examinations. Chapter 1 NCERT Solutions will help you in completing your homework on time. These NCERT Solutions will help an individual to increase concentration and you can solve questions of supplementary books easily.
Knowing our Numbers Class 6 MCQ: Here, You will get Class 6 MCQ on Knowing our Numbers at free of cost. Along with you can take online MCQ test for Knowing our Numbers to get higher marks in Class 6 Examinations.
☑️ Class :6th☑️ Subject : Maths ☑️ Chapter 1- Knowing Our Numbers ☑️ Topic : Exercise 1.1- Question 1 🙏Like | Share | Subscribe|🙏 Press 🔔icon for more...
Answer 1. 10; 160; 1891 17; 2464; Answer 2 Round off each factor to its greatest place a. $300 \times 400 = 120000$ b. $5000 \times 3000= 15000000$ c. $30 \times 500= 15000$ d. $500 \times 2000=10000$ Answer 3 Use below steps to solve these 1. Examine the digit at tens place. 2. if the digit at tens place < 5, replace each one of the digits at tens and ones or units place by 0 and keep all ...
Our teachers have developed really good Multiple Choice Questions covering all important topics in each chapter which are expected to come in upcoming tests and exams, as MCQs are coming in all exams now therefore practice them carefully to get full understanding of topics and get good marks.Download the latest questions with multiple choice answers for Class 6 Knowing our Numbers in pdf or ...